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Solubility Calculator

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Calculate the solubility of inorganic salts (such as KBr, NaCl, KNO3) in water at different temperatures. Features high-precision experimental databases, linear interpolation, step-by-step math derivation, and a visual saturation simulator.

🔬 Salt Solubility Calculation

Solution Temperature (°C)

23 °C

0°C50°C100°C

Enter to calculate saturation status and precipitation

Saturation Status
Saturated

Solubility Limit at 23°C

66.68 g / 100g H₂O

Dissolved Solute

66.68g / 66.68g max

⚠️ Precipitated Excess (Solid): 13.32 g

📈 Solubility vs Temperature Curve (KBr)
0°C20°C40°C60°C80°C100°C0g26g52g79g105g
Temp: 23°C | Solubility: 66.68g
📝 Step-by-Step Derivation

Based on standard reference solubilities at 20°C (65g) and 30°C (70.6g), linear interpolation is performed as follows:

1. Temperature Solubility Interpolation

Estimate solubility at the target temperature using linear interpolation:

S(T)=S(Tmin)+(TTmin)×S(Tmax)S(Tmin)TmaxTminS(T) = S(T_{min}) + (T - T_{min}) \times \frac{S(T_{max}) - S(T_{min})}{T_{max} - T_{min}}

Calculation:

S(23)=65+(2320)×70.6653020=66.68 g/100g H2OS(23) = 65 + (23 - 20) \times \frac{70.6 - 65}{30 - 20} = 66.68 \text{ g/100g H}_2\text{O}

2. Calculate Maximum Soluble Mass for a Given Solvent

If your actual water solvent mass is mwaterm_{\text{water}}, the maximum solute mass mmaxm_{\text{max}} that can dissolve at temperature T is calculated as:

mmax=S(T)×mwater100m_{\text{max}} = S(T) \times \frac{m_{\text{water}}}{100}

Calculation:

mmax=S(23)×100100=66.68×100100=66.68 gm_{\text{max}} = S(23) \times \frac{100}{100} = 66.68 \times \frac{100}{100} = 66.68 \text{ g}

3. Saturation Check & Solid Precipitation

Since the added solute mass maddedm_{\text{added}} (80g) is greater than the maximum solubility capacity mmaxm_{\text{max}} (66.68g), the solution is saturated, and solid crystals will precipitate:

mprecipitated=maddedmmax=8066.68=13.32 gm_{\text{precipitated}} = m_{\text{added}} - m_{\text{max}} = 80 - 66.68 = 13.32 \text{ g}


Mastering Inorganic Salt Solubility Calculations (Solubility Calculator)

In laboratory experiments, chemical formulations, and academic homework, calculating the solubility of inorganic salts at a specific temperature is a fundamental task. For instance, when tasked to calculate the solubility of potassium bromide at 23°C, chemists rely on experimental datasets and Linear Interpolation formulas to find the exact saturation limit.

You can use the interactive Solubility Calculator at the top of this page to choose your target inorganic salt (such as KBr, NaCl, KNO3, or CuSO4), input the temperature and solvent mass, and obtain the maximum dissolved mass instantly alongside a step-by-step math solver derivation.

Principles of Solubility and Linear Interpolation Algorithm

Dissolving most inorganic salts in water is an endothermic process, meaning their solubility limits increase as the temperature rises. When precise experimental measurements are not directly cataloged for a specific integer temperature, chemists apply Linear Interpolation:

S(T)=S(Tmin)+(TTmin)×S(Tmax)S(Tmin)TmaxTminS(T) = S(T*{min}) + (T - T*{min}) \times \frac{S(T*{max}) - S(T*{min})}{T*{max} - T*{min}}

Where TT is the target temperature, TminT_{min} and TmaxT_{max} are the closest lower and upper experimental temperature bounds in the reference database, and S(Tmin)S(T_{min}) and S(Tmax)S(T_{max}) are their corresponding reference solubility limits.

Calculation Case Study: KBr Solubility at 23°C

Let's look at the classic chemistry homework question: "Calculate the solubility of potassium bromide at 23°C." First, we reference the standard experimental dataset for inorganic salts in water:

Temperature (°C)KBr Solubility (g/100g H₂O)NaCl Solubility (g/100g H₂O)
054.035.7
2065.036.0
3070.636.3
100104.939.8

Solubility standards compiled from the PubChem Potassium Bromide Solubility Section and the Wikipedia Inorganic Solubility Table.

Since 23°C lies between 20°C (S20=65.0gS_{20} = 65.0\text{g}) and 30°C (S30=70.6gS_{30} = 70.6\text{g}), we apply the interpolation formula:

S(23)=65.0+(2320)×70.665.03020=65.0+3×0.56=66.68 g/100g H_2OS(23) = 65.0 + (23 - 20) \times \frac{70.6 - 65.0}{30 - 20} = 65.0 + 3 \times 0.56 = 66.68\text{ g/100g H}\_2\text{O}

This means that at 23°C, a maximum of 66.68 g of anhydrous potassium bromide can dissolve in 100 grams of water.

Solvent Scaling & Saturation Calculation Steps

In practical chemical experiments and lab formulations, you often need to calculate the maximum capacity and check the saturation state for a specific mass of solvent water and added solute.

1. Calculate Maximum Soluble Mass for a Given Solvent

If your actual water solvent mass is mwaterm_{\text{water}}, the maximum solute mass mmaxm_{\text{max}} that can dissolve at temperature TT is:

mmax=S(T)×mwater100m*{\text{max}} = S(T) \times \frac{m*{\text{water}}}{100}

2. Saturation Check & Solid Precipitation

We compare your added solute mass maddedm_{\text{added}} with the maximum solubility capacity mmaxm_{\text{max}}:

  • Unsaturated State: If maddedmmaxm_{\text{added}} \le m_{\text{max}}, the solute dissolves completely with zero solid precipitation (mprecipitated=0m_{\text{precipitated}} = 0).

  • Saturated State: If madded>mmaxm_{\text{added}} > m_{\text{max}}, the solute exceeds the carrying capacity of the solvent. The solution is saturated, and solid crystals will precipitate:

mprecipitated=maddedm_maxm*{\text{precipitated}} = m*{\text{added}} - m\_{\text{max}}

Numerical Example (48°C, 207g Water, 129.5g KBr Solute)

Step 1: Calculate KBr Solubility at 48°C
Since 48°C lies between 40°C (S40=76.1gS_{40} = 76.1\text{g}) and 60°C (S60=85.9gS_{60} = 85.9\text{g}), linear interpolation yields:

S(48)=76.1+(4840)×85.976.16040=80.02 g/100g H_2OS(48) = 76.1 + (48 - 40) \times \frac{85.9 - 76.1}{60 - 40} = 80.02\text{ g/100g H}\_2\text{O}

Step 2: Calculate Maximum Capacity for 207g Water
Substitute the solvent mass into the scaling equation:

m_max=80.02×207100=165.64 gm\_{\text{max}} = 80.02 \times \frac{207}{100} = 165.64\text{ g}

Step 3: Perform Saturation Check
With added solute madded=129.5gm_{\text{added}} = 129.5\text{g} and max capacity mmax=165.64 gm_{\text{max}} = 165.64\text{ g}:
Since 129.5g165.64g129.5\text{g} \le 165.64\text{g}, the solution is unsaturated. The KBr dissolves completely with zero crystal precipitation (0g0\text{g}).

Solubility Preparation Checklist and Safety Warning

When preparing saturated solutions, be sure to pay attention to its thermodynamic characteristics:

Frequently Asked Questions (FAQ)

Q: How does the Solubility Calculator interpolate values?
A: The calculator holds standard experimental solubilities for common salts from 0°C to 100°C. When you enter a custom temperature, the algorithm automatically identifies the closest upper and lower bounding data points in the database and runs a linear interpolation to estimate the exact solubility.

Q: What is the difference between a saturated and unsaturated solution?
A: A saturated solution holds the maximum amount of solute that can dissolve at that specific temperature; any further solute added will remain as a solid precipitate at the bottom of the beaker. An unsaturated solution holds less than the maximum limit, allowing more solute to dissolve.

Q: Why does solubility usually increase with temperature?
A: For most solids (like KNO3 and KBr), the dissolution process absorbs heat (endothermic). According to Le Chatelier's principle, raising the temperature shifts the equilibrium in the direction that absorbs heat, thereby increasing solubility.

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